three numbers A,B,C the second is less than the first number by 30 and third number is less than first number by 37.then the second number is more than the third number by how much percent.
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let the numbers are x,y,z
similarly 2nd is y= x-30
and third is z =x-37
let take x to be 100 then
y= 70
z=63
then 70/100 = 0.7 is 1%
63÷0.7=90%
100 - 90 =10
ans is 10 %
similarly 2nd is y= x-30
and third is z =x-37
let take x to be 100 then
y= 70
z=63
then 70/100 = 0.7 is 1%
63÷0.7=90%
100 - 90 =10
ans is 10 %
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