Three numbers and in continued proportion, whose mean
proportional is 12 and the sum of the remaing
two numbers
is 26, the
find these numbers
Answers
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Step-by-step explanation:
let the there numbers be
a,b,c
As they are in continued
Proportion
b^2=ac
mean is 12
∴b=12
So, 12^2 =ac
144=ac
c=144/a
Sum of two numbers is
a+c=26
a+144/a=26
Solving,
=> a^2+144-26a=0
=> a^2-18a-8a+144=0
=> a(a-18) -8(a-18)=0
=> (a-18) (a-8)=0
∴a=18 or a=8
c=8 c=18
∴ The numbers are :-
8,12,18 or 18,12,8
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