Three numbers are chosen at random without replacement from {1 , 2, 3,...8} .The propability that thier minimum is 3 , given that their maximum is 6. is ..ans. is 1/5.
plzz explain..
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A be the event that maximum is 6.
B be event that minimum is 3
P(A) = 5C2 / 8C3 (the numbers < 6 are 5)
P(B) = 5C2 / 8C3 (the numbers > 3 are 5)
P(A ∩ B) = 2C1 / 8C3
Required probability is = P(A ∩ B) / P(A)
The correct option is D.
B be event that minimum is 3
P(A) = 5C2 / 8C3 (the numbers < 6 are 5)
P(B) = 5C2 / 8C3 (the numbers > 3 are 5)
P(A ∩ B) = 2C1 / 8C3
Required probability is = P(A ∩ B) / P(A)
The correct option is D.
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