Three numbers are chosen at random without replacement the probability that the minimum of the chosen numbers is 3 or their maximum is 7;is
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Number of elements in sample space = 10C3 =120
According to the question 3 & 7 must get chosen and the third no. should be between them (ie 4 or5 or 6)as per condition .
So, no of favourable cases = 3C1 =3
Therefore required probablity = 3/120 = 1/40
Approve the answer if correct .
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