Question

Three numbers are chosen randomly from first 100 numbers find probability such that all three numbers is divisible by 2 and 3.

Answer 1

here there are 100 numbers

so n(S)=100

according to the eventA:the number divisible by 2 and 3 from 1 to 100 is

A=(6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96)

n(A)=16

P(A)=n(A)÷n(S)

=16÷100

=4÷25

so brobability is 4÷25