Three numbers are in A.P. If the sum of these numbers be 27 and the product 648, find the numbers
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Given: Sum of first three terms is 27
Let us assume the first three terms as
a – d, a, a + d [where a is the first term and d is the common difference]
So,
sum of first three terms is a – d + a + a + d
= 27 3a = 27 a = 9
It is given that the product of three terms is 648
So,
a³ – ad²= 648
Substituting the value of a = 9,
we get 9³– 9d²= 648
729 – 9d² = 648
81 = 9d²
d = 3 or d = – 3
Hence, the given terms are a – d, a, a + d which is 6, 9, 12.
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