three numbers are in AP and their sum is 18 sum of their square is 140 find the numbers
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Answered by
10
let the no. be a-d,a,a+d
a-d+a+a+d = 18
3a = 18
a = 6
a²+d²-2ad+a²+a²+d²+2ad = 140
3a²+2d² = 140
3×36+2d² = 140
2d² = 140-108
2d² = 32
d² = 16
d = ±6
so the no.'s are 0,6,12
please mark it as the brainliest answer
a-d+a+a+d = 18
3a = 18
a = 6
a²+d²-2ad+a²+a²+d²+2ad = 140
3a²+2d² = 140
3×36+2d² = 140
2d² = 140-108
2d² = 32
d² = 16
d = ±6
so the no.'s are 0,6,12
please mark it as the brainliest answer
Answered by
4
the numbers are (-10) , 6 & 22
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