Three numbers are in AP . If the sum of these numbers be 27 and the product 648 , find the numbers.
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Let the three numbers be (a-d) , a , (a+d)
(a-d) + a + (a+d) = 27
=> 3a = 27
=> a = 27/3
=> a = 9
(a-d) × a × (a+d) = 648
=> (9-d) × 9 × (9+d) = 648
=> (9-d) × (9+d) = 648/9
=> 81 - d^2 = 72
=> d^2 = 81 - 72
=> d^2 = 9
=> d = √9
=> d = ± 3
when d = 3,
nos. = (9-3) , 9 (9+3)
= 6 , 9 , 12
when d = - 3,
nos. = (9+3) , 9 (9-3)
= 12 , 9 , 6
Therefore the nos. are = 6 , 9 and 12
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