three numbers are in ap if the sum of these numbers is 21 and product is 648 . find the numbers
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Factors of 140 = 2 x 2 x 5 x 7
2 + 10 + 7 = 19
a - d, a, a+d
a - d + a + a +d = 18
3a = 18
a = 6
(a-d)² + a² + (a+d)² = 140
(6-d)² + (6+d)² = 140 - 36
36 + d² - 12d + 36 + d² -12d = 104
2d² = 104 - 72 = 32
d² = 32/2 = 16
d = 4
so numbers a - d = 6-4 = 2; a= 6; a+d = 6+4+ 10
2, 6, 10
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