three numbers are in AP if their sum is 27 and product is 648 find the numbers
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a-d, a, a+d are in ap
sum=27
a-d+a+a+d=27
3a=27
a=27/3
a=9
product =648
(a-d) (a+d)a=648
(a^2 - d^2)(a) =648
(81-d^2)(9)=648
81-d^2=648/9
81-d^2=72
d^2=81-72
d^2=9
d=3
a=9,d=3
a-d= 9-3=6
a=9
a+d=9+3=12
numbers are 6,9,12
sum=27
a-d+a+a+d=27
3a=27
a=27/3
a=9
product =648
(a-d) (a+d)a=648
(a^2 - d^2)(a) =648
(81-d^2)(9)=648
81-d^2=648/9
81-d^2=72
d^2=81-72
d^2=9
d=3
a=9,d=3
a-d= 9-3=6
a=9
a+d=9+3=12
numbers are 6,9,12
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