Question

three numbers are in AP. if their sum is 27 and their product is 648, find the numbers.

Answer 1

let 1st number be a-d,a,a+d
a+d+a+a-d=27
3a=27
a=9
(a+d)(a)(a-d)=648
(a+d)(a-d)=648/9
a^2-d^2=72
81-72=d^2
√9=d
d=3
a=9
a+d=12
a-d=6

Answer 2

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