Three numbers are in ap. Their product is 48 and the sum of their reciprocals is 11÷12.
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Sum = 15
a-d + a + a+d = 15
3a = 15
a = 5
= (a−d) * (a) * (a+d)
= (a^2−d^2) = 80/5
= 25 - d^2 = 16
d^2 = 9
d = 3
The values will be 8,5,2.
a-d + a + a+d = 15
3a = 15
a = 5
= (a−d) * (a) * (a+d)
= (a^2−d^2) = 80/5
= 25 - d^2 = 16
d^2 = 9
d = 3
The values will be 8,5,2.
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