Question

Three numbers are in AP their sum is 12 and this product is 48. Find the AP.​

Answer 1

Answer:

A.P is 2,4,6

Step-by-step explanation:

Let the three terms in AP be (a-d), a, (a+d)

given, sum of terms=12

so, (a-d)+a+(a+d)=12

then, 3a=12

and, a=4

Now given that, product of terms =48

so, (a-d)*a*(a+d)=48

>a(a²-d²)=48

>4(16-d²)=48

>16-d²=12

>d²=4

>d=+2,-2

Hence A.P. is 2,4,6