Question

three numbers are in arithmetic progression.their sum is 18 and their product is 18. determine the three numbers.

Answer 1

Please refer to the attachment. Hope it helps❤❤✌✌☺☺

Answer 2

Answer:

let the three numbers x,x+d,x+d+d

where d = common difference

x+x+d+x+d+d = 18

3x + 3d = 18

x + d = 6

x = 6 - d

x(x+d)(x+d+d) = 18

sub x = 6 - d

6 - d(6 - d + d)(6 - d + d + d) = 18

6-d(6)(6+d) = 18

(36-6d)×(36+6d) = 18

1296 - 36d^2 = 18

also, 72-2d^2 = 1

-2d^2 = 1-72 = -71

d^2 = -71/(-2) = 35.5

d = √35.5