Question

three numbers are in arithmetic progression their sum is 8 and product is 19440 find those numbers​

Answer 1

Answer:

simple apply the formula to see it and

if u then also not get it

then

then f*ck yourself

Answer 2

Step-by-step explanation:

let the number be

a-1,a,a+1

sum of three number is 8

(a-1)+a+(a+1)=8

3a=8

a=8/3

product of three number is 19440

(a-1)×a×(a+1)=19440

(a^2-b^2)a=19440

a^3-ab^2=19440

put the value of a

8/3^2-8/3×b^2=19440

after solving

b=101.781(approx)

after this put the value of a in the number which we let and u have a answer

I hope its help u