Question

three numbers are in arithmetic progression their sum is 81 and product is 19440 find those numbers​

Answer 1

Step-by-step explanation:

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the no. is 24 27 30

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Answer 2

Let the three nos. be a-d , a , a+d

Sum=> a-d+a+a+d=81

3a=81

a=27

Product=> (a-d)(a)(a+d)=19440

a(a^2-d^2)=19440

27(729-d^2)=19440

729-d^2=720

d^2=729-720

d=+3 or -3

Case 1: If d=+3

a-d=27-3=24

a=27

a+d=27+3=30

Case 2: If d= -3

a-d=27+3=30

a=27

a+d=27-3=24

In either of the cases the numbers are the same, that is; 24, 27 and 30.