Question

Three numbers are in continued proportion whose mean proportional is 12 and the sum of the remaining two numbers 26,then find the answer? ​

Answer 1

Step-by-step explanation:

let the there numbers be

a,b,c

As they are in continued

Proportion

b

2

=ac

mean is 12

∴b=12

So, 12

2

=ac

144=ac

c=144/a

Sum of two number is

a+c=26

a+

a

144

=26

Solving,

=a

2

+144−26a=0

=a

2

−18a−8a+144=0

=a(a−18)−8(a−18)=0

=(a−18)(a−8)=0

∴a=18 or a=8

c=8 c=18

∴ The numbers are :-

8,12,18 or 18,12,8

Answer 2

Answer:

let the there numbers be

a,b,c

As they are in continued

Proportion

b

2

=ac

mean is 12

∴b=12

So, 12

2

=ac

144=ac

c=144/a

Sum of two number is

a+c=26

a+

a

144

=26

Solving,

=a

2

+144−26a=0

=a

2

−18a−8a+144=0

=a(a−18)−8(a−18)=0

=(a−18)(a−8)=0

∴a=18 or a=8

c=8 c=18

∴ The numbers are :-

8,12,18 or 18,12,8

Step-by-step explanation:

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