Three numbers are in continued proportion, whose mean proportional is 12 and the sum
of the remaining two numbers is 26, then find these numbers.
antinued proportion.
Answers
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let the there numbers be
a,b,c
As they are in continued
Proportion
b² =ac
mean is 12
∴b=12
So, 12² =ac
144=ac
Sum of two number is
a+c=26
Solving,
=a² +144−26a=0
=a² −18a−8a+144=0
=a(a−18)−8(a−18)=0
=(a−18)(a−8)=0
∴a=18 or a=8
c=8 c=18
∴ The numbers are :-
8,12,18 or 18,12,8
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