Three numbers are in continued proportion whose mean proportional is 25 and the sum of the remaining two numbers is 36. Find the numbers.
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Answer:
let the there numbers be
a,b,c
As they are in continued
Proportion
b2=ac
mean is 12
∴b=12
So, 122=ac
144=ac
c=144/a
Sum of two number is
a+c=26
a+a144=26
Solving,
=a2+144−26a=0
=a2−18a−8a+144=0
=a(a−18)−8(a−18)=0
=(a−18)(a−8)=0
∴a=18 or a=8
c=8 c=18
∴ The numbers are :-
8,12,18 or 18,12,8
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