Question

three numbers are in ratio 1 : 2 : 3 the sum of their cubes is 7776 find the number​

Answer 1

Let the numbers be x, 2x, and 3x

A/C to question:

=x^3+(2x)^3+(3x)^3=7776

=x^3+8x^3+27x^3=7776

=36x^3=7776

=x^3=7776/36

=x^3=216

=x=6

Therefore by substituting the value of x in the assumed numbers, we get the following numbers:

x=6

2x=2*6=12

3x=3*6=18

So, the numbers are 6, 12, 18.

Hope it helps you :)

Answer 2

Answer:

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