three numbers are in ratio 2 : 3 :
4 the sum of the largest and the smallest number is 120 find the number
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Answered by
1
Let the numbers be 2x, 3x and 4x
Now atq
4x + 2x =120
6x =120
X=20
So 1st number = 20*2=40
2nd number = 20*3=60
3rd number = 20*4=80
Now atq
4x + 2x =120
6x =120
X=20
So 1st number = 20*2=40
2nd number = 20*3=60
3rd number = 20*4=80
Rishav2408:
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Answered by
0
Hey there!
Let the numbers be 2x,3x and 4x respectively.
Smallest no. = 2x
Largest no, = 4x
ATQ,
4x + 2x = 120
6x = 120
x = 20
Hence, the numbers are:
♦ 2x = 2 x 20 = 40
♦ 3x = 3 x 20 = 60
♦ 4x = 4 x 20 = 80
Hope It Helps You!
Let the numbers be 2x,3x and 4x respectively.
Smallest no. = 2x
Largest no, = 4x
ATQ,
4x + 2x = 120
6x = 120
x = 20
Hence, the numbers are:
♦ 2x = 2 x 20 = 40
♦ 3x = 3 x 20 = 60
♦ 4x = 4 x 20 = 80
Hope It Helps You!
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