Question

three numbers are in ratio 2:3:4 the sum of their cube is 33957 find the numbers

Answer 1

Let the numbers be 2a, 3a and 4a

According to question,

(2a)^3 + (3a)^3 + (4a)^3 = 33957

=> 8a^3 + 27a^3 + 64a^3 = 33957

=> 99 a^3 = 33957

=> a^3 = 343

=> a = 7

First number = 7 × 2 = 14

Second number = 7 × 3 = 21

Third number = 7 × 4 = 28

Answer 2

Hope this answer is helpful to you and please mark me as brainliest