Question

three numbers are in ratio 3 ratio 4 ratio 5. the sum of their cubes is 27000. find the number​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$the \: numbers \: are \: 15 \: 20 \: and \: 25$

Step-by-step explanation:

$number \: ratio = 3:4:5 \\ suppose \: the \: numbers \: are \: 3x \: 4x \: and \: (5x \\ (3 {x)}^{3}+ (4 {x)}^{3} + (5 {x)}^{3} = 27000 \\ {x}^{3}(27 + 64 + 125 ) = 27000 \\ {x}^{3} \times 216 = 27000 \\ {x}^{3} = 125 \\ {x}^{3} = {(5)}^{3} \\ x = 5 \\ \\ the \: numbers \: are \: 3 \times 5 = 15 \\ 4 \times 5 = 20 \\ 5 \times 5 = 25$