Math, asked by ramanrsingh123, 1 year ago

Three numbers are in ratio of 2:3:5. The sum of there square is 608. Find out the numbers.

Answers

Answered by hemantku29
1

Three numbers are in the ratio 2:3:5

The sum of three numbers = 608

Therefore, sum of terms of the ratio = (2+3+5) = 10

First number =(2/10) * 608 = 121.6

Second number =(3/10)* 608 = 182.4

Third number =(5/10)* 608 = 304.0

Hence, the numbers are :- 121.6, 182.4 and 304 .

To check, the sum of three numbers must be equal to 608

= (121.6+182.4+304.0) = 608

=) 608 = 608

I hope it helps you....

Answered by rehan7682
1

Answer:

Let the ratio be 2x,3x,5x

Sum of ratio terms=2x+3x+5x=10x

First number=2x/10x×608

=608/5x

=121.6

second number=3x/10×608

=182.4

third number=5x/10x×608

=608/2

=304

The numbers are=121.6,182.4,304

CHECK=121.6+182.4+304=608

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hope it helps

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