Question

Three numbers are in ratio of 4:5:7 if the sum of the largest and smallest number is 72 more than the third number, find the numbers

Answer 1

Let the numbers be 4a, 5a and 7a respectively

According to question

( 4a +7a) = 5a + 72

=> 11a = 5a +72

=> 6a = 72

=> a = 12

First number = 48

Second number = 60

Third number = 84

Answer 2

Let the common multiple be x.

So,

The numbers are 4x,5x,7x respectively

By the given condition

4x+7x=5x+72

11x=5x+72

11x-5x=72

6x=72

x=72/6

x=12

SO ,the common multiple is 12

Three numbers are:
4x=4(12)=48
5x=5(12)=60
7x=7(12)=84.

Final Answer:
The numbers are 48,60 &84

hope this helps!!!