Question

Three numbers are in the 2:3:4. The sum of their cubes is 33957. Find the Numbers.​

Answer 1

Answer:

Let the numbers be 2x, 3x and 4x

sum of cubes = 33957

⇒(2x)³ + (3x)³ + (4x)³ = 33957

⇒8x³ + 27x³ + 64x³ = 33957

⇒99x³ = 33957

⇒x³ = 33957/99 = 343

⇒x = ∛343 = 7

Numbers are:

2x = 2×7 = 14

3x = 3×7 = 21

4x = 4×7 = 28

hopes it helps!!!

Answer 2

Answer:

Let the we take are 2x 3x&4x

sum of their cubes is 33957

(2x)^3+(3x)^3+(4x)^3=33957

8x^3+27x^3+64^3=33957

99x^3=33957

x^3=33957/99

x=3√343

x=7

So, 2x=2*7=14

3x=3*7=21

4x=4*7=28

I Hope it helps you...