three numbers are in the ratio 1/2:1/3:1/4.If the sum of their squares is 244 find the numbers
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Let th ratio be x
So now (1/2x)^2+(1/4x)^2+(1/3x)^2=244
1/4x^2+1/9x^2+1/16x^2=244
Now taking LCM=144
(36x^2+16x^2+9x^2)/144=244
61x^2/144=244
(244*144)/61=x^2
576=x^2
Root on both sides
X=24
Now
1/2x=24/2=12
1/3x=24/3=8
1/4x=24/4=6
So now (1/2x)^2+(1/4x)^2+(1/3x)^2=244
1/4x^2+1/9x^2+1/16x^2=244
Now taking LCM=144
(36x^2+16x^2+9x^2)/144=244
61x^2/144=244
(244*144)/61=x^2
576=x^2
Root on both sides
X=24
Now
1/2x=24/2=12
1/3x=24/3=8
1/4x=24/4=6
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