Question

Three numbers are in the ratio 1:2:3 and sum of their cubes is 288. Find the numbers.

Answer 1

Answer:

Step-by-step explanation:

let the no. be 1x, 2x, 3x

(1x)^3 + (2x)^3 + (3x)^3 = 288

              1x + 8x + 27x = 288

                             36x = 288

                                 x = 288/36

                                  x = 8

Therefore

1x = 1*x = 1*8 = 8

2x = 2*x = 2*8 = 16

3x = 3*x = 3*8 = 24

Answer 2

Answer:

see explanation

Step-by-step explanation:

let,

length of 1st number be x

length of 2nd number be 2x

length of 3rd number be 3x

now, according to question,

x³+(2x)³+(3x)³ = 288

=> x³+8x³+27x³ = 288

=> 36x³ = 288

=> x³ =288/36

=> x³ = 8

=> x =2

so, 1st number =x=2

2nd number =2x=2x2=4

3rd number=3x=3x2=6