Question

Three numbers are in the ratio 1:2:3 and the sum of their cubes is 4500. Find the numbers.​

Answer 1

numbers are in the ratio 1:2:3

let the numbers be x, 2x, 3x

sum of cubes = 4500

x^3 + (2x)^3 + (3x)^3 = 4500

x^3 + 8x^3 + 27x^3 = 4500

36x^3 = 4500

x^3 = 4500/36

x^3 = 125

x = (125)^(1/3)

x = 5

Answer 2

Answer:

let the number of 1k,2k,3k respectively since the sum of cubes(1k)³+(2)³+(3)³-4500

--k³(36)-4500

-- k-5

hence the number of 5,10,15