Question

Three numbers are in the ratio 1:2:3. If the sum of the cubes of these numbers is 7776 then find the numbers.​

Answer 1

Let no be x

Acc to que

1st=1x

2nd=2x

3rd=3x

There sum:-

(1x)^3+(2x)^3+(3x)^3=7776

1x^3+8x^3+27x^3=7776

36x^3=7776

x^3=7776/36

x^3=216

x=6

So

1st=6

2nd=12

3rd=18

Hope it helps u☺

Answer 2

Answer:

hope it helps you friends