Math, asked by bhagyyalakshmi0, 2 days ago

Three numbers are in the ratio 1: 2:3, if the sum of their cubes is 62,208, then the numbers are the successive multiples of

Answers

Answered by Jashkapopara

0

Answer:

let number be x , 2x and 3x

x3 + 8x3 + 27 x3 = 62,208

36x3 = 62,208

x3 = 62,208 / 36

x3 = 1728

x = cube root 1728

x = 12

Numbers = 12 , 24 and 36

Therefore they are successive multiples of 12

Step-by-step explanation:

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