Question

Three numbers are in the ratio 1:2:3. The sum of their cubes is 0.098784. Find the numbers

Answer 1

The answer is given below :

The ratio of the numbers is 1 : 2 : 3.

Let, x be the common multiple.

Then the numbers are x, 2x and 3x.

Given that, sum of the cubes of the numbers

= 0.098784

=> (x)³ + (2x)³ + (3x)³ = 0.098784

=> x³ + 8x³ + 27x³ = 0.098784

=> 36x³ = 0.098784

=> x³ = 0.14³

=> x = 0.14

So, the numbers are

0.14, 2×0.14 and 3×0.14

i.e., 0.14, 0.28 and 0.42

Thank you for your question.

Answer 2

Heya ☺

Given that

Sum of the cubes of 3 numbers = 0.098784

Solution

according to question,

(x)^3 + (2x)^3 + (3x)^3 = 0.098784

=> x^3 + 8x^3 + 27x^3 = 0.098784

=> 36x^3 = 0.098784/6

=> x^3 = 0.016464/36

=> x = 0.14

1st number = 0.14

2nd number = 2 × 0.14 = 0.28

3rd number = 3 × 0.14 = 0.42

Hence , the required numbers are 0.14 , 0.28 and 0.42.


Thanks :)))

Hope it helps you !!!!