THREE NUMBERS ARE IN THE RATIO 1:3:2 AND SUM OF THEIR CUBES IS EQUAL TO 2.304. FIND THE SUM OF THE NUMBERS.
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let the numbers be h, 3h, 2h
according to question
h^3+27(h^3)+8(h^3)=2.304
36h^3=2.304
h=[2.304/36]^{1/3}
numbers are h, 34,2h
according to question
h^3+27(h^3)+8(h^3)=2.304
36h^3=2.304
h=[2.304/36]^{1/3}
numbers are h, 34,2h
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