Math, asked by beracahtechinnah57, 3 months ago

Three numbers are in the ratio 1:3:5. If the sum of their squares is 875, find the smallest of the three numbers.

Answers

Answered by hihihiihihih
12

Answer:

5, 15, 25

Step-by-step explanation:

Let the three numbers be 1x, 3x, and 5x.

Sum of their squares = 875

=> (1x)² + (3x)² + (5x)² = 875

1x² + 9x² + 25x² = 875

35x² = 875

x² = 875/35

x² = 25

x = √25

x = 5

Therefore, the three sides are:

1x = 1 x 5 = 5

3x = 3 x 5 = 15

5x = 5 x 5 = 25

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