three numbers are in the ratio 2:3:4 . if the sum of the squares of the extremes is 180 , then find middle number
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Answered by
9
Let the extremes be 2x and 4x.
According to the question,
(2x×2x)+(4x×4x)=180
4x square + 16x square=180
20x square=180
X square=180÷20
X= root 9
X=3
There for the middle non = 3x = 3×3 = 9
According to the question,
(2x×2x)+(4x×4x)=180
4x square + 16x square=180
20x square=180
X square=180÷20
X= root 9
X=3
There for the middle non = 3x = 3×3 = 9
Answered by
1
Given :
Three numbers are in ratio 2:3:4
The sum of squares of extreme is 180.
To find : The middle number.
Solution :
Three numbers are in ratio 2:3:4 so let's assume that the numbers are 2x, 3x and 4x.
We are given that sum of squares of extreme is 180.
HERE 2 and 4 are extreme so according to the given condition the equation will be
( 2x)² + (4 x) ² = 180
taking squares we get
4x ² + 16 x² =180
solving we get
20 x² =180
x² = 180 / 20
x² = 9
x =3
putting value of x in the terms
2x = 2 x3 =6
3x = 3 x3 = 9
4 x = 4 x3 = 12
Hence the numbers are 6, 9 and 12. The middle number is 9.
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