Three numbers are in the ratio 2: 3: 4. the sum of their cubes is 33957.find the numbers.
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Answered by
5
Let the numbers be 2x, 3x and 4x
(2x)³+(3x)³+(4x³)=33957
8x³+27x³+64x³=33957
99x³=33957
x³=343
x=∛343
x=7
2x=7×2=14
3x=7×3=21
4x=7×4=28
∴The numbers are 14, 21 and 28
(2x)³+(3x)³+(4x³)=33957
8x³+27x³+64x³=33957
99x³=33957
x³=343
x=∛343
x=7
2x=7×2=14
3x=7×3=21
4x=7×4=28
∴The numbers are 14, 21 and 28
vishalkumar36:
thank you but from where the 14,21 and 28 has came
Answered by
4
Let the three no. be 2x, 3x, 4x
According to question-
(2x)³+(3x)³+(4x)³= 33957
8x³+27x³+64x³ = 33957
99x³ = 33957
x³ = 33957/99
x³ = 343
x = ³√343
x = 7
So, 2x = 2×7 = 14
3x = 3×7= 21
4x = 4×7 = 28
According to question-
(2x)³+(3x)³+(4x)³= 33957
8x³+27x³+64x³ = 33957
99x³ = 33957
x³ = 33957/99
x³ = 343
x = ³√343
x = 7
So, 2x = 2×7 = 14
3x = 3×7= 21
4x = 4×7 = 28
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