Question

Three numbers are in the ratio 2:3:5 and the sum of their squares in 608. Then find the number​

Answer 1

dear army

i hope my answer is correct

Answer 2

Answer

Suppoze the three numbers=2z,3z and 5z.

A.P.Q.

(2z)²+(3z)²+(5z)²=608

or 4z²+9z²+25²=608

or 38z²=608

or z²=608÷38

or z²=16

or z²=(4)²

or z=4

Hence,the three numbers are

2×z=2×4=83×z=3×4=125×z=5×4=20