Question

Three numbers are in the ratio 2 : 3 : 5 . The sum of their squares is 608 . Find the three numbers.

Answer 1

Step-by-step explanation:

The answer of your question is in above picture please give me thanks❤

Answer 2

Step-by-step explanation:

Let us assume the three number be 2a, 3a, 5a

$\bf Then,$

Given, sum of squares of three numbers is 608

$\bf \: i.e. \: (2a)^{2}+ (3a)^{2} + (5a)^{2} = 608$

$\bf4a^{2} + 9a^{2} + 25a^{2} = 608$

$\bf38a ^{2} = 608$

$\bf \: a^{2} = \frac{ \: 608 \: }{ \: 38 \: }$

$\bf \: a^{2} = 16 a = \sqrt{16}$

$\bf \: a = \sqrt{(4 × 4) }$

$\bf \: a = \sqrt{(5^{2})}$

$\bf = > \red{a = 4}$

$\bf∴The \: numbers \: are, 2a = 2 × 4 = 8$

$\bf3a = 3 × 4 = 12$

$\bf5a = 5× 4 = 20$