three numbers are in the ratio 2:3:5.the sum of their squares is 608. find the three numbers.
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Answered by
17
Hii there
Let the numbers be
2x , 3x abd 5x
(2x)^2 + (3x)/2 + (5x)^2 = 608
=> 4x^2 + 9x^2 + 25x^2 = 608
=> 38x^2 = 608
=> x^2 = 608/38
=> x = Root 16 = 4
2x = 2×4 = 8
3x = 3×4 = 12
5x = 5×4 = 20
Hope it helps dear......
Let the numbers be
2x , 3x abd 5x
(2x)^2 + (3x)/2 + (5x)^2 = 608
=> 4x^2 + 9x^2 + 25x^2 = 608
=> 38x^2 = 608
=> x^2 = 608/38
=> x = Root 16 = 4
2x = 2×4 = 8
3x = 3×4 = 12
5x = 5×4 = 20
Hope it helps dear......
Answered by
6
2^2:3^3:5^5=608
4:9:25=608
4x+9x+25x=608
38x=608
x=16
three numbers are 32 48 and 90
4:9:25=608
4x+9x+25x=608
38x=608
x=16
three numbers are 32 48 and 90
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