Three numbers are in the ratio 2:3:5.the sum of their squares is 608.the number is
Answers
Answered by
5
#AlexaRousey here!!
Let the meet of ratio be x.
Hence three numbers are 2x, 3x and 5x.
According to question ;
=) (2x)^2 + (3x)^2 + (5x)^2 = 608
=) 4x^2 + 9x^2 + 25x^2 = 608
=) 38x^2 = 608
=) x^2 = 608/38
=) x^2 = 16
=) x = 4
Hence numbers are 2*4, 3*4 and 5*4
= 8,12 and 20.
Thanks!!
Let the meet of ratio be x.
Hence three numbers are 2x, 3x and 5x.
According to question ;
=) (2x)^2 + (3x)^2 + (5x)^2 = 608
=) 4x^2 + 9x^2 + 25x^2 = 608
=) 38x^2 = 608
=) x^2 = 608/38
=) x^2 = 16
=) x = 4
Hence numbers are 2*4, 3*4 and 5*4
= 8,12 and 20.
Thanks!!
Answered by
4
GIVEN
Three Numbers are in ratio of 2:3:5
The sum of their squares is 608
TO FIND
Those Numbers
SOLUTION
Let the numbers be 2x, 3x and 5x
According to the question,
(2x)^2 + (3x)^2 + (5x)^2 = 608
=> 4x^2 + 9x^2 + 25x^2 = 608
=> 38x^2 = 608
=> x^2 = 608/38
=> x^2 = 16
=> x = 4
If x = 4 , the numbers are
2x = 8
3x = 12
5x = 20
Hence the numbers are 8,12 and 20 (Ans)
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