Question

Three numbers are in the ratio 2:3:7 and their sum is 72. Find the numbers.​

Answer 1

$\Large{\underline{\underline{\mathfrak{\red{\bf{Solution}}}}}}$.

$\Large{\underline{\mathfrak{\orange{\bf{Given}}}}}$

• Three numbers are in the ratio 2:3:7
• their sum is 72

$\Large{\underline{\mathfrak{\orange{\bf{Find}}}}}$

• These number.

$\Large{\underline{\underline{\mathfrak{\red{\bf{Explanation}}}}}}$.

Let,

• first Number be = 2x
• Second Number be = 3x
• Third Number be = 7x

Acc. to question,

➡2x + 3x + 7x = 72

➡12x = 72

➡x = 72/12

➡x = 6

$\Large{\underline{\underline{\mathfrak{\red{\bf{Hence}}}}}}$.

• First number be = 2x = 2×6 = 12
• Second number be = 3x = 3×6 = 18
• Third Number be = 7x = 7×6 = 42

_______________

Answer 2

Answer:

let the ratio is x

ATQ........

2x + 3x + 7x=72

12x = 72

x=6

so, the numbers are 2x= 12

3x= 18

7x= 42.