Question

Three numbers are in the ratio 2:4:5 and are such that the sum of their square is equal to 4500, then find the smallest number among it​

Answer 1

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Answer 2

$\mathfrak{\huge{Solution:-}}$

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Let the three numbers be - 2x , 4x and 5x

Then, thier squares will be - 4x², 9x²,25x²

According to the question, the sum of thier squares = 4500

So,

4x²+16x²+25x² = 4500

45x² = 4500

x² = $\frac{4500}{45}$

x² = 100

x = √100

x = 10.

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The numbers are:-

2x = 20

4x = 40

5x = 50

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Hence, here the smallest number is

20. The smallest square - 4x² = 400