Question

Three numbers are in the ratio 2:y:5. The third number is greater than the first one by 21. Find the numbers if sum of numbers is 70

Answer 1

Hi ,

It is given that ,

Ratio of three numbers = 2 : y : 5

Let first number = 2a

Second number = ay

Third number = 5a

According to the problem given ,

5a = 2a + 21

5a - 2a = 21

3a = 21

a = 21/3

a = 7 ---( 1 )

Sum of the three numbers = 70

2a + ay + 5a = 70

7a + ay = 70

7 × 7 + 7y = 70 [ from ( 1 ) ]

49 + 7y = 70

7y = 70 - 49

7y = 21

y = 21/7

y = 3 ,

Therefore ,

Required numbers are ,

First number = 2a = 2×7 = 14

Second number = ay = 7× 3 = 21

Third number = 5a = 5 × 7 = 35

I hope this helps you.

: )