Question

Three numbers are in the ratio 3: 4:5 and the sum of their cubes is 1728
find the numbers.​

Answer 1

Answer:

let the numbers be 3x, 4x and 5x. then,

(3x)^3 + (4x)^3 +(5x)^3 = 1728

27x^3 + 64x^3 + 125x^3 =1728

216x^3 = 1728

x^3 =1728/216

x. = 8. =(2)^3

x= 2

so, the numbers are -

(3*2)=6

(4*2)=8

(5*2)=10

the numbers are 6 , 8 and 10.

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