Question

three numbers are in the ratio 3:4:5.if the sum of the largest and the smallest numbers exceeds the third number by 64,find the numbers​

Answer 1

Answer:

the numbers are 48,64,80

Step-by-step explanation:

given ratio=3:4:5

let the numbers be 3x,4x,5x,

according to the question

5x+3x=4x+64

8x=4x+64

8x-4x= 64

4x=64

x=64/4

x=16

3x=3×16=48

4x=4×16=64

5x=5×16=80

Answer 2

Answer:

numbers=

3*16=48

4*16=64

5*16=80

Step-by-step explanation:

answer attached...