Question

Three numbers are in the ratio 3: 4: 5: .if the sum of the largest and the smallest equals the sum of the third and 52, find the numbers.

Answer 1

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let the 1st,2nd and 3rd numer be 3x,4x and 5x respectively

ATQ
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$3x + 5x = 4x + 52 \\ 8x - 4x = 52 \\ x = \frac{52}{4} \\ x = 13$
So,the 1st no. is=3x= 3×13=39
2nd no.= 4x=13×4= 52
3rd no.=5x= 5×13= 65
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Answer 2

$\underline{\bold{Solution :}}$

Let the numbers be 3x, 4x & 5x

$\underline{\bold{Note :-}}$ Here, third one refers to 4x

According to Question,

5x + 3x = 4x + 52

=> 8x - 4x = 52

=> 4x = 52

=> x = 52/4

=>$\boxed{ x = 13}$

1st One = 3x = 3(13)
= 39

2nd One = 4x = 4(13)
= 52

3rd One = 5x = 5(13)
= 65

Hence, the numbers are 39, 52 & 65

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