Question

Three numbers are in the ratio 3:4:5 If the sum of their cubes is 27,000 Find the numbers...…(Friends please answer me ASAP)

Answer 1

Answer:

let the number be 3x,4x and 5x

according to question

(3x)^3+(4x)^3+(5x)^3 = 27,000

27x^3+64x^3+125x^3 =27,000

x^3(27+64+125)=27,000

X^3=27,000/216

x=cube root of (27,000/216)

x=cube root 125

x = 5

Answer 2

Hey there!

Given,

Let the numbers be 3x , 4x , 5x respectively.

ACQ,

(3x)³ + (4x)³ + (5x)³ = 27000

⇒ 27x³ + 64x³ + 125x³ = 27000

⇒ 216x³ = 27000

⇒ x³ = 27000/216

⇒ x³ = 125

⇒ x = ∛125

⇒ x = 5

Hence, the numbers are:

3x = 3 * 5 = 15

4x = 4 * 5 = 20

5x = 5 * 5 = 25