Question

Three numbers are in the ratio 3:4:5. If the sum of their cubes is 216000, find the largest of these three numbers.

Answer 1

Answer:

50

Step-by-step explanation:

let the common factor be x

number are 3x, 4x, 5x

According to the question

$(3x)^{3}$+$(4x)^{3} + (5x)^{3}$ = 216000

27$x^{3}$+ 64$x^{3}$ + 125$x^{3}$ = 216000

216$x^{3}$ = 216000

$x^{3}$ = 216000/216

    = 1000

x = $\sqrt[3]{1000}$

   = 10

largest number = 5x= 5*10 = 50

Answer 2

Answer:

50

Step-by-step explanation:

let the common factor be x

number are 3x, 4x, 5x

According to the question

+ = 216000

27+ 64 + 125 = 216000

216 = 216000

= 216000/216

   = 1000

x =

  = 10

largest number = 5x= 5*10 = 50