Question

three numbers are in the ratio 3:4:5 sum of their cube is 1728 find the number

Answer 1

The answer is in the attachment.

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Answer 2

Answer:

Let common factor be x

$\therefore$ Numbers will 3x,4x,5x

Sum of cube = 1728

$( 3x) ^{3} + (4 {x}^{3} ) + (5x ^{3}) = 1728$

$27 {x}^{ 3} + 64 {x}^{3} + 125 {x}^{3} = 1728$

$216 {x}^{3} = 1728$

${x}^{3} = \frac{1728}{216}$

${x}^{3} = 8$

$x = \sqrt[3]{8}$

$x = 2$

Numbers are :

$3x = 3 \times 2 = 6$

$4x = 4 \times 2 = 8$

$5x = 5 \times 2 = 10$