Question

Three numbers are in the ratio 3:4:5. The sum of the largest and the smallest equals the sum of the third and 52. The smallest number is

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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♦ Let the common ratio between the numbers be 'x'.


♦ Then,

first number = 3x

second number = 4x

third number = 5x.



♦ Now, it is give that the sum of largest and smallest equals the sum of third and 52.


• Here, 3x is smallest and 5x is largest.

→→→ 3x + 5x = 4x + 52

=> 8x = 4x + 52

=> 8x - 4x = 52

=> x = 52/4

=> x = 13


•°• The numbers are,

first number = 3x = 3(13) = 39

second number = 4x = 4(13) = 52

third number = 5x = 5(13) = 65.


♥ Out of them, 39 is the smallest.
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Thank you..

Answer 2

Answer:

Smallest number is 39.

Step-by-step explanation:

Let the number be x.

So, numbers formed will be 3x, 4x and 5x.

According to the question,

Sum of Largest and Smallest equals sum of Third and Fifty-Two.

Then,

$3 \times + 5 \timesx = 4x + 52 \\ 8x = 4x + 52 \\ 8x - 4x = 52 \\ 4x = 52 \\ x = 13$

So, Numbers formed are as Follows:

3x= 3(13)=39

4x=4(13)=52

5x=5(13)=65

So, smallest number is 39.